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Tach signal / knock sensor power increase?
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Tach signal on my 16v comes off the coil. Disconnect it and the only =
thing that happens is...no tachometer.
Larry
----- Original Message -----=20
From: ATS - Patrick Bureau=20
To: Ryan H ; scirocco-l@scirocco.org=20
Sent: Wednesday, April 02, 2003 8:55 AM
Subject: RE: Tach signal / knock sensor power increase?
humm i though the TAch signal (rpm) was the pin 7 of the TZH box not =
the
knock box.
ATS - Patrick Bureau - txrocco@sbcglobal.net
=3D>-----Original Message-----
=3D>From: scirocco-l-admin@scirocco.org
=3D>[mailto:scirocco-l-admin@scirocco.org]On Behalf Of Ryan H
=3D>Sent: Tuesday, April 01, 2003 11:20 PM
=3D>To: scirocco-l@scirocco.org
=3D>Subject: Tach signal / knock sensor power increase?
=3D>
=3D>
=3D>OK guys, can someone tell me what wire to/from the knock box
=3D>(16V) is the tach signal? And also, look at this pic.... in the
=3D>bottom right it says something about increasing power by
=3D>unconnecting two grounds... um, anyone try this? Where are they
=3D>connected together? At the harness connection?
=
=3D>http://home.mindspring.com/~tberk/_uimages/Knock-Sensor-Diagram.JPG
=3D>
=3D>
=3D>_______________________________________________
=3D>Scirocco-l mailing list
=3D>Scirocco-l@scirocco.org
=3D>http://neubayern.net/mailman/listinfo/scirocco-l
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<DIV><FONT face=3DArial size=3D2>Tach signal on my 16v comes off the =
coil. =20
Disconnect it and the only thing that happens is...no =
tachometer.</FONT></DIV>
<DIV> </DIV>
<DIV><FONT face=3DArial size=3D2>Larry</FONT></DIV>
<BLOCKQUOTE=20
style=3D"BORDER-LEFT: #000000 2px solid; MARGIN-LEFT: 5px; MARGIN-RIGHT: =
0px; PADDING-LEFT: 5px; PADDING-RIGHT: 0px">
<DIV style=3D"FONT: 10pt arial">----- Original Message ----- </DIV>
<DIV=20
style=3D"BACKGROUND: #e4e4e4; FONT: 10pt arial; font-color: =
black"><B>From:</B>=20
<A href=3D"mailto:txrocco@sbcglobal.net" =
title=3Dtxrocco@sbcglobal.net>ATS -=20
Patrick Bureau</A> </DIV>
<DIV style=3D"FONT: 10pt arial"><B>To:</B> <A =
href=3D"mailto:rhock99@epix.net"=20
title=3Drhock99@epix.net>Ryan H</A> ; <A =
href=3D"mailto:scirocco-l@scirocco.org"=20
title=3Dscirocco-l@scirocco.org>scirocco-l@scirocco.org</A> </DIV>
<DIV style=3D"FONT: 10pt arial"><B>Sent:</B> Wednesday, April 02, 2003 =
8:55=20
AM</DIV>
<DIV style=3D"FONT: 10pt arial"><B>Subject:</B> RE: Tach signal / =
knock sensor=20
power increase?</DIV>
<DIV><BR></DIV>humm i though the TAch signal (rpm) was the pin 7 of =
the TZH=20
box not the<BR>knock box.<BR><BR>ATS - Patrick Bureau - <A=20
=
href=3D"mailto:txrocco@sbcglobal.net">txrocco@sbcglobal.net</A><BR><BR><B=
R>=3D>-----Original=20
Message-----<BR>=3D>From: <A=20
=
href=3D"mailto:scirocco-l-admin@scirocco.org">scirocco-l-admin@scirocco.o=
rg</A><BR>=3D>[<A=20
=
href=3D"mailto:scirocco-l-admin@scirocco.org">mailto:scirocco-l-admin@sci=
rocco.org</A>]On=20
Behalf Of Ryan H<BR>=3D>Sent: Tuesday, April 01, 2003 11:20 =
PM<BR>=3D>To: <A=20
=
href=3D"mailto:scirocco-l@scirocco.org">scirocco-l@scirocco.org</A><BR>=3D=
>Subject:=20
Tach signal / knock sensor power =
increase?<BR>=3D><BR>=3D><BR>=3D>OK guys,=20
can someone tell me what wire to/from the knock box<BR>=3D>(16V) is =
the tach=20
signal? And also, look at this pic.... in the<BR>=3D>bottom =
right it=20
says something about increasing power by<BR>=3D>unconnecting two =
grounds...=20
um, anyone try this? Where are they<BR>=3D>connected =
together? At=20
the harness connection?<BR>=3D><A=20
=
href=3D"http://home.mindspring.com/~tberk/_uimages/Knock-Sensor-Diagram.J=
PG">http://home.mindspring.com/~tberk/_uimages/Knock-Sensor-Diagram.JPG</=
A><BR>=3D><BR>=3D><BR>=3D>______________________________________=
_________<BR>=3D>Scirocco-l=20
mailing list<BR>=3D><A=20
=
href=3D"mailto:Scirocco-l@scirocco.org">Scirocco-l@scirocco.org</A><BR>=3D=
><A=20
=
href=3D"http://neubayern.net/mailman/listinfo/scirocco-l">http://neubayer=
n.net/mailman/listinfo/scirocco-l</A><BR><BR><BR>________________________=
_______________________<BR>Scirocco-l=20
mailing list<BR><A=20
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href=3D"mailto:Scirocco-l@scirocco.org">Scirocco-l@scirocco.org</A><BR><A=
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